0.44+0.22x=0.09-0.6x+x^2

Solution for 0.44+0.22x=0.09-0.6x+x^2 equation:

0.44+0.22x=0.09-0.6x+x^2

We move all terms to the left:

0.44+0.22x-(0.09-0.6x+x^2)=0

We get rid of parentheses

-x^2+0.6x+0.22x-0.09+0.44=0

We add all the numbers together, and all the variables

-1x^2+0.82x+0.35=0

a = -1; b = 0.82; c = +0.35;
Δ = b2-4ac
Δ = 0.822-4·(-1)·0.35
Δ = 2.0724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.82)-\sqrt{2.0724}}{2*-1}=\frac{-0.82-\sqrt{2.0724}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.82)+\sqrt{2.0724}}{2*-1}=\frac{-0.82+\sqrt{2.0724}}{-2}
$